Determine the measure of bases a and b and height h of the given trapezoid. Given the coordinates of the points, the distance is calculated through the equation,
d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)
Base 1: (-2,2) and (1,-2):
d= sqrt ((-2 - 1)² + (2 - -2)²) = 5
Base 2: (2,5) and (11, -7)
d = sqrt ((2 - 11)² + (5 - -7)²) = 15
Height: (-2,2) and (2, 5)
h = sqrt ((-2 -2)² + (2 - 5)²) = 5
The equation for the area of the trapezoid is,
A = (1/2)(base1 + base2)h
Substituting the known values,
A = (1/2)(5 + 15)(5) = 50
ANSWER: 50 square units
