The height above the ground (in feet) of a ball dropped from the top of a 30-foot-tall building after t seconds is given by the polynomial −16t2+30. what is the height of the ball after 12 second? write your answer without units.
If h(t)=-16t²+30, then the ball hits the ground, or h(t)=0, at: 0=-16t²+30 16t²=30 t²=1.875 t=1.37 seconds The ball is on the ground after 1.37 seconds, so, after 12 seconds the height of the ball is 0 ☺☺☺☺
