Respuesta :
An apparatus like the one cavendish used to find g has a large lead ball that is 7.7 kg in mass and a small one that is 0.061 kg. their centers are separated by 0.05 m. find the force of attraction between them. the value of the universal gravitational constant is 6.67259 × 10−11 n · m2 /kg2 . answer in units of n.
Answer:
The force of attraction between them is [tex](1.2536).10^{-8}N[/tex]
Explanation:
We are going to use the Newton's Gravitational Law to solve this exercise.
The law states that :
The gravitational force between two objects is proportional to their masses and inversely proportional to the square of the distance between their centers.
The equation is :
[tex]F_{G}=\frac{G.m_{1}.m_{2}}{d^{2}}[/tex]
Where ''[tex]G[/tex]'' is the universal gravitational constant.
Where ''[tex]m_{1}[/tex]'' and ''[tex]m_{2}[/tex]'' are the masses of the objects.
Where ''[tex]d[/tex]'' is the distance between the centers of the objects.
If we replace all the data in the equation :
[tex]F_{G}=\frac{(6.67259).10^{-11}\frac{N.m^{2}}{kg^{2}}.(7.7kg).(0.061kg)}{(0.05m)^{2}}[/tex]
[tex]F_{G}=(1.2536).10^{-8}N[/tex]