Determine the molar solubility (s) of ag2co3 in a buffered solution with a ph of 4.987 using the systematic treatment of equilibrium. ksp(ag2co3) = 8.46 × 10–12; ka1(h2co3) = 4.45 × 10–7; ka2(h2co3) = 4.69 × 10–11.
pH = 11.50 is the same as pOH = 2.50 and thus [OH-] = 10^-2.50 M.
Ksp = 5.0X10^-17 = [Zn(2+)]*[OH-]^2 = [Zn(2+)]*10^-5.0
Hence [Zn(2+)] = 5.0X10^-12 M. This is the molar solubility of Zn(OH)2 in a buffer solution with a pH of 11.50.