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barnuts

We know that the oxidation number of sodium Na is +1, and oxygen O is -2, therefore:

2 (+1) + 2 x + 5 (-2) = 0

2 + 2x – 10 = 0

2x = 8

x = 4

The oxidation number is +4

samueladesida43

The oxidation number of sulfur in Na2S2O5 is +4

HOW TO CALCULATE OXIDATION NUMBER:

  • The oxidation number of an element in a compound can be calculated using the following process:

Naturally;

  1. Oxygen has an oxidation state of -2
  2. Sodium has an oxidation state of +1

Na2S2O5

+1 (2) + x(2) - 2(5) = 0

2 + 2x - 10 = 0

2 + 2x = 10

2x = 10 - 2

2x = 8

x = 4.

Therefore, the oxidation number of sulfur in Na2S2O5 is +4

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