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A 258-ml sample of mek, an industrial solvent, is found to have a mass of 0.599 g at and 100c. what is the molar mass of mek?

Respuesta :

Kalahira
Correct answer is : 72.0 g/mole If we assume Ideal Gas Law, PV = nRT. n = PV/RT = ((0.988 atm)*(0.258 L))/((0.0821 L*atm/mole*K)*(100 + 273.15)) = 0.00832 moles Molar mass = 0.599 g/0.00832 moles = 72.0 g/mole; your answer is E.

Answer:

The ans is 71.1 g/mol

Explanation:

Mass of MEK (m) = 0.599 g

Volume of MEK (V) = 258 ml = 0.258 L

Temperature (T) = 100 C = 100 +273 = 373 K

Pressure = 1 atm

Based on the ideal gas equation:

[tex]PV = nRT[/tex]

where n = number of moles and R = gas constant 0.0821 Latm/mol-K

[tex]n = \frac{PV}{RT}[/tex]

[tex]n = \frac{1*0.258}{0.0821*373} = 0.00842 moles[/tex]

number of moles is given as:

[tex]n = \frac{mass MEK}{molar mass MEK} \\\\molar mass = \frac{mass MEK}{n} = \frac{0.599}{0.00842}  = 71.14 g/mol[/tex]

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