The solution contains four ions
Ca2+, Na+, OH−, and CO3^-2
so there are following four combinations are possible
NaOH : this is highly soluble in water so will not form precipitate
Ca(OH)2: this is highly soluble in water so will not form precipitate
Na2CO3: again soluble in water so will not form precipitate
CaCO3 : this is not soluble in water (it has low solubility product) so this will form precipitate most likely