pH = pKa + log([A^-]/[HA])
[A^-] = [KF] = 0.43 M, [HA] = [HF] = 0.20 M
pKa = -logKa = -log(6.8x10^-4) = 3.17
pH = 3.17+ log(0.43 / 0.20) = 3.50
You can determine the [H3O^+] by using the equation for pH
pH = -log[H3O^+]
[H3O^+] = 10^-pH = 10^-3.50 = 3.16x10^-4 M