Answer: The molecular geometry for [tex]CH_3^+[/tex] is trigonal planar.
Explanation
Formula used for calculating molecular weight:
[tex]\text{Number of electrons}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom = 4
N = number of monovalent atoms bonded to central atom = 3
C = charge of cation = +1
A = charge of anion = 0
Now we have to determine the hybridization of the [tex]CH_3^+[/tex] molecules.
[tex]\text{Number of electrons}=\frac{1}{2}\times [4+3-1]=3[/tex]
Bond pair electrons = 3
Lone pair electrons = 0
The number of electrons are 6 that means the hybridization will be [tex]sp^2[/tex] and the electronic geometry of the molecule will be trigonal planar.
As there are no lone pair of electrons, the molecular geometry also will be trigonal planar.
