To
determine the volume of LiNO3 present in 0.184 M LiNO3 solution, first note
that the concentration of LiNO3 is expressed in units of molarity or moles per
liter solution. Thus, given the molarity, 0.184 M, and the number of moles,
0.113 mol LiNO3, the volume of LiNO3 in milliliters can then be determined using
this equation:
0.113
mol LiNO3/0.184 mol/L x 1000 mL/L = 614.13 mL LiNO3
