Solution for this problem is we will be using the following formula:
Work done by applied force) = Force (applied) x s x cos θ
Where:
Force applied = 12 N
s = 13 m long
Angle = 17
So plugging in the values:
=>W (a) = 12 x 13 x cos 17
= 12 x 12.43196182
= 149.1835 J
Work done by the applied force : Wp = 149,184 J
Work is the transfer of energy caused by the force acting on a moving object
Work is the product of force with the displacement of objects.
Can be formulated
W = Work, J, Nm
F = Force, N
S = distance, m
Force and displacement of objects are vector . Multiplication of both is in accordance with the dot product concept of two vectors. Whereas W is a scalar quantity. Then if there is an angle formed by the force F and the displacement S is θ, then it can be formulated
W = F cos θ.S
There are 4 forces on the cart , so there are 4 work that occurs
= Fp.cos θ. S
= 12. cos 17. 13
Wp = 149,184 J
the magnitude is the same as the force applied by the applied force (Fp) but the opposite direction = -149,184 J
the direction is upward with an angle of θ = 90°, with F = mg
Wn = Fn.cos 90. S
Wn = mg cos 90. 13
Wn = 0
work done by the gravitational force = Wg
Wg = Fg. cos 90. S.
Wg = mg cos 90. 13
Wg = 0
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