The problem is missing some parts. But here are the
questions and answers.
a.
Use the work-energy theorem to find its speed
just as it left the ground
Initial Kinetic Energy = GPE + KE
1/2 * m * V^2 = m * g * h + 1/2 * m * v^2
V^2 = 2 * 9.8 * 15.6 + 25.6^2
=sqrt 968.96
V (initial speed) ≈ 31.130 m/s
b.
Use the work-energy theorem to look for its
maximum height.
H = 968.96 / 2 * 9.8 ≈
49.44 m
