A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate the centripetal force exerted on the ball.

m = 0.5 kg, the mass of the ball
r = 0.4 m. the radius from the center of the circle to the ball
v = 4.0 m/s, the tangential velocity of the ball as the ball rotates
counterclockwise about the center of the circle.

Refer to the diagram shown below.

By definition, the centripetal acceleration of the ball is
a = v²/r = (4 m/s)²/(0.4 m) = 40 m/s²
The centripetal force exerted on the ball is
F = m*a = (0.5 kg)*(40 m/s²) = 20 N

Answer: 20 N

snehashish65 snehashish65 · Answer 2 · 2021-10-26T13:00:56+02:00

The centripetal force exerted on the ball is of 20 N.

Given data:

The mass of ball is, m = 0.5 kg.

The radius of circular path is, r = 0.4 m.

The speed of ball is, v = 4.0 m/s.

The expression for the centripetal force acting on the ball is given as,

[tex]F = \dfrac{mv^{2}}{r}[/tex]

Solving as,

[tex]F = \dfrac{0.5 \times 4.0^{2}}{0.4}\\\\F =20 \;\rm N[/tex]

Thus, the centripetal force exerted on the ball is of 20 N.

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