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A game has a rectangular board with an area of 44 in2. There is a square hole near the top of the game board in which you must not toss in a bean bag. The square has side lengths of 3 in. What is the probability of not tossing the bag through the hole?

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nsiahkobina0
The area of the hole would be 9 in^2 if it is considered that every space withing the board has equal possibilities then 

9/44 = 0.204 = 20.4% 

Answer:

The probability of not tossing the bag through the hole is:

[tex]\dfrac{35}{44}=0.7954[/tex]

Step-by-step explanation:

We are given a rectangular board of area 44 square inches.

Also there is a square hole near the top of the game board with side length 3 inches.

Hence, the area of the square hole is: (side)^2

Area of square hole=(3)^2

hence, Area of square hole=9 square inches.

The probability of not tossing the bag through the hole is:

Area excluding the square hole/Area of board.

we know that:

Area excluding square hole= Area of board-Area of square hole

                                             =44-9

                                           =35 square inches.

Hence, the probability is:

[tex]\dfrac{35}{44}=0.7954[/tex]

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