Hello!
We have the following data:
F (force) =?
m (mass) = 40 kg
a (acceleration) = 0.93 m / s²
k (spring constant) =?
x (spring deformation) = 0.82 m
Let us first find the applied force, through the following formula:
[tex]F = m*a[/tex]
[tex]F = 40*0,93[/tex]
[tex]F = 37,2\:N[/tex]
Now let's find the spring constant, using Hooke's formula
[tex]F = k*x[/tex]
[tex]37,2 = k*0,82[/tex]
[tex]0,82k = 37,2[/tex]
[tex] k = \frac{37,2}{0,82} [/tex]
[tex]\boxed{\boxed{k \approx 45,3\:N/m}}\end{array}}\qquad\checkmark [/tex]
Answer:
We have a spring constant with about 45 N / m
