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Which of the following equations is equivalent to 4[x + 2(3x – 7)] = 22x – 65?
28x – 7 = 22x – 65

28x – 56 = 22x – 65

10x – 14 = 22x – 65

16x – 28 = 22x – 65

Respuesta :

4[x + 2(3x - 7)] = 22x - 65

4[x + 6x - 14] = 22x - 65

4x + 24x - 56 = 22x - 65

28x - 56 = 22x - 65

JeanaShupp

Answer: [tex]28x-56= 22x - 65[/tex]

Step-by-step explanation:

The given expression: [tex]4[x + 2(3x - 7)] = 22x - 65[/tex]

Consider L.H.S. [tex]4[x + 2(3x -7)][/tex]

Solving the bracket present inside by using distributive property, we get

[tex]4[x + 6x -14]=4[7x-14][/tex]

Now, Multiplying 4 inside the bracket by using distributive property:-

[tex]28x-56[/tex]

Hence, the given function is equivalent to [tex]28x-56= 22x -65[/tex]