so, is two integers, and they must be consecutive, meaning, the next one will have to be either 1 before the first or one after... anyhow.
let's say the first integer is "a".
then a consecutive integer to that one will be just 1 hop away, or say "a + 1", so there, those are the two integers.
now, we know that
[tex]\bf \stackrel{\textit{square of the first is decreased by 17}}{a^2-17}~~=~~\stackrel{\textit{4 times the second}}{4(a+1)}
\\\\\\
a^2-17=4a+4\implies a^2-4a-21=0\implies (a-7)(a+3)=0
\\\\\\
a=
\begin{cases}
\boxed{7}\\
-3
\end{cases}[/tex]
so, is a positive integer, so it can't be -3.
what's the second integer? well is a + 1.
