contestada

Consider a balloon that has a volume V. It contains n moles of gas, it has an internal pressure of P, and its temperature is T. If the balloon is heated to a temperature of 15.5T while it is placed under a high pressure of 15.5P, how does the volume of the balloon change?

Respuesta :

b.) it stays the same

Answer: The temperature will not change and will remain T.

Explanation: Accoding to ideal gas law:

[tex]PV=nRT[/tex]

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

[tex]P_1[/tex]= initial pressure

[tex]V_1[/tex]= initial volume

[tex]T_1[/tex]= initial temperature

[tex]P_2[/tex]= final pressure

[tex]V_2[/tex]= final volume

[tex]T_2[/tex]= final temperature

Putting in the values:

[tex]\frac{PV}{T}=\frac{15.5PV_2}{15.5T}[/tex]

[tex]T_2=T[/tex]