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An ideal spring is hung vertically from the ceiling. when a 2.0-kg mass hangs at rest from it the spring is extended 6.0 cm from its relaxed length. an upward external force is then applied to the block to move it upward a distance of 16 cm. while the the block is being extended by the force, the work done by the spring is

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The force for a spring can be determined from Hooke's law: F=-kx, where k is the spring constant and x is the length of the spring. The work done can be determined using the equation: W=Fd. If you want to know the work done by the spring, you can substitute the force for a spring into the work equation, so the equation becomes W=-Fxd. If we solve the equation, F=mg where g is the acceleration due to gravity, so F=(2.0 kg)(9.8 m/s^2)= 19.6 N. We have the force. The work done is W=(19.6 N)(0.06 m)(0.16 m)=.188 J

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