Questions involving accelerating objects, including those in free fall, can be solved using three equations
y = 1/2at2 + v0t + y0
v = v0 + at
vf2 = v02 + 2 a (y - y0)
In this case, only the first equation is needed.
Since the object is falling the final height is 0 meters, the initial height is 370 m, and the acceleration is -9.8ms-2
Since the object is dropped, the initial velocity is 0.
So:-4.9t²+370=00=4.9t²-370t²=370/4.9=75.51t=±√75.51=8.7 seconds☺☺☺☺
