Respuesta :
Answer:
0.48
Step-by-step explanation:
Given : Mean = 17 hours
Standard deviation = 6 hours
n = population size =600
To Find: what is the margin of error for a 95% confidence interval?
Solution:
n= 600
[tex]\sigma = 6[/tex]
z = 1.96 for a 95 % confidence interval;
Margin of error formula:
[tex]ME=\frac{z \times \sigma}{\sqrt{n}}[/tex]
Substitute the values
[tex]ME=\frac{1.96 \times 6}{\sqrt{600}}[/tex]
[tex]ME=0.48[/tex]
Hence the margin of error for a 95% confidence interval is 0.48