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What is the equation of a line that is parallel to −x+3y=6 and passes through the point (3, 5) ?

Respuesta :

3y=6+x
y=(6+x)/3
y=2+x/3
y=mx+b
y=x/3+b
so m(slope) is 1/3
use the point (3, 5), sub this for x and y
5=3/3+b
5-1=b
b=4
therefore, y=x/3+4
or y=(1/3)x+4 (you can write it like this as well)

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