Answer:
Part 1) option A [tex]3.30\frac{\$}{gallon}[/tex]
Part 2) Table 3 see the attached figure
Step-by-step explanation:
Part 1)
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]
The table represent a direct variation
The unit rate for one gallons of gasoline is equal to the constant of proportionality k
Let
x-----> the number of gallons
y-----> the price
so
For [tex]x=2\ gallons[/tex], [tex]y=\$6.60[/tex]
Find the value of k
[tex]6.60/2=k[/tex]
[tex]k=3.30\frac{\$}{gallon}[/tex]
Part 2)
Let
x------> string instruments
y------> percussion instruments
[tex]ratio=\frac{x}{y}[/tex]
table 1
the ratio is equal to
[tex]ratio=\frac{2}{3}[/tex]
table 2
the ratio is equal to
[tex]ratio=\frac{2}{5}[/tex]
table 3
the ratio is equal to
[tex]ratio=\frac{2}{1}=2[/tex]
table 4
the ratio is equal to
[tex]ratio=\frac{2}{4}=\frac{1}{2}[/tex]
