A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle.

Respuesta :

The answer is  9 inches squared.

Answer:

The area is 9 inches squared

Step-by-step explanation:

The area of a rectangle is the multiplication of the lenght and the width

Let A be the area, L the lenght and W the width

A = LW

The given lenght is [tex]\sqrt[3]{81}[/tex] inches and the given width is [tex]3^{(\frac{2}{3})}[/tex] inches

But using a property of exponentials you can rewrite the width as:

[tex](3^{2}) ^{\frac{1}{3} }[/tex]

There is another property of exponentials which says that: [tex]n^{\frac{1}{k} } = \sqrt[k]{n}[/tex]

So, the width can be written as: [tex]\sqrt[3]{3^{2} }[/tex]

Calculating the area:

[tex]A=\sqrt[3]{81}(\sqrt[3]{9})[/tex]

The multiplication of two cube roots is the cube root of the multiplication of the two numbers

Therefore:

[tex]A=\sqrt[3]{(81)(9)} = \sqrt[3]{729}[/tex]

A = 9 [tex](inches)^{2}[/tex]