Solve the system
4x = y
2x^2 − y = 0 (Note: Use " ^ " to denote exponentiation.)
In the 2nd equation, subst. 4x for y: 2x^2 - (4x) = 0. Then,
2x^2 - 4x = 0. Factor out one x: x(2x - 4) = 0. This produces two roots, which are {0, 2}.
Next, find y. y=4x. So, if x: {0, 2}, we get y: {0, 8}
Roots may be (0,0) and (2,8). It's important that you check your results by subst. their x- and y-coordinates into the original equations.
