Respuesta :
For two objects with a finite constant mass, Fg is inversely proportional to the square of the distance between them. As r gets smaller the gravitational force increases. When the two objects are touching Fg is highest. But the mass of an object is focussed at its centre, the centre of mass. When the objects are touching their centres of mass are still separated. The graph has a vertical asymptote at r=0, implying an infinite gravitational force.
Graph has a vertical asymptote at r = 0, implying an infinite gravitational force.
Given :
[tex]\rm F_g = -\dfrac{Gm_1m_2}{r^2}[/tex]
where G is the gravitational constant, [tex]\rm m_1[/tex] and [tex]\rm m_2[/tex] are the masses of the objects and r is the distance between the objects centers.
Solution :
As the given formula we can see that,
[tex]\rm F_g \; \alpha \; \dfrac{1}{r^2}[/tex]
When r gets smaller the gravitational force increases imply that when the two objects are touching, [tex]F_g[/tex] is highest. But the mass of an object is focussed at its centre, the centre of mass. When the objects are touching their centres of mass are still separated.
Graph has a vertical asymptote at r = 0, implying an infinite gravitational force.
For more information, refer the link given below
https://brainly.com/question/24783651
