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Lyle stirs 5.0 grams of salt into a beaker of water. He then adds 15.0 grams of pure iodine to the mixture. If the total mass of the new mixture is 225 grams, what is the mass of the water

Respuesta :

lazygenius514

Answer:

Given data:

Mass of solution = 225 grams.

Mass of salt = 5 grams

Mass of iodine = 15 grams.

Mass of water = ?

Solution:

Mass of solution = Mass of water + Mass of salt + Mass of Iodine

225 = Mass of water + 5 + 15

Mass of water =  225 - 20

                        = 205

                                          Hence  Mass of water = 205 grams.


carminahershey

Answer:

205 grams.

Explanation:

The mass of a mixture is equal to the sum of the masses of its components. Since the total mass of Lyle's mixture is 225 grams, the sum of all three components of the mixture must equal 225 grams.

Since 225 g - 20.0 g = 205 g, the mass of the water must be 205 grams.

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