Respuesta :
if that 2 is an exponent
[tex](n+7)^2=(n+7)(n+7)=[/tex]
[tex](n+7)(n)+(n+7)(7)=[/tex]
[tex]n^2+7n+7n+49=[/tex]
[tex]n^2+14n+49[/tex]
or you coud use the formula
[tex](a+b)^2=a^2+2ab+b^2[/tex]
so
[tex](n+7)^2=n^2+2(n)(7)+7^2=n^2+14n+49[/tex]
answer is C
[tex](n+7)^2=(n+7)(n+7)=[/tex]
[tex](n+7)(n)+(n+7)(7)=[/tex]
[tex]n^2+7n+7n+49=[/tex]
[tex]n^2+14n+49[/tex]
or you coud use the formula
[tex](a+b)^2=a^2+2ab+b^2[/tex]
so
[tex](n+7)^2=n^2+2(n)(7)+7^2=n^2+14n+49[/tex]
answer is C
The little 2 next to (n+7) means squared. Therefore you have to put the same numbers twice.
(n+7)(n+7) = n2+7n+7n+49 : then add the same numbers so in this case 7n+7n which gives you :
n2+14n+49
(n+7)(n+7) = n2+7n+7n+49 : then add the same numbers so in this case 7n+7n which gives you :
n2+14n+49