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A ball is thrown upward into the air so that its height, h, in feet, after t seconds is modeled by the function h(t) = 56t – 16t2. What is the velocity, in feet per second, of the ball after 2 seconds?

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-8
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48

Respuesta :

jorel1380
h(t)=56t-16t²
h(2)=56(2)-16(4)=112-64=48
The ball will be 48 ft high
Its' initial velocity was given by 56t, or 56 ft./sec
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Answer:

A

Step-by-step explanation:

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