The perimeter is 110 in. The length of the rectangle is 4 times as long as the width. what is the width of the rectangle? ill make you brainliest if you showed your work or how you did it.

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09-11-2017
Mathematics

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The perimeter is 110 in. The length of the rectangle is 4 times as long as the width. what is the width of the rectangle? ill make you brainliest if you showed your work or how you did it.

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lilxiong lilxiong · Answer 1 · 2017-11-11T23:36:39+01:00

To start, let's define our variable, which is x. x will represent the width of the rectangle. Next, since you know that the length is 4 times as long as the width, it will be represented by 4x. Now, since you know that the perimeter of a figure is the sum of the length of all the sides of the rectangle, you can express the perimeter with this expression: 4x+4x+x+x
Then, you set the expression to the perimeter, which is 110.
4x+4x+x+x=110
Combine like terms: 10x=110
And solve for x: x=11
Now that you have solved for x, which represents the width of the rectangle, you now know that your answer is 11.