A 3.0 kg mass moving to the right at 1.4 m/s collides in a perfectly inelastic collision with a 2.0 kg mass initially at rest. what will the velocity of the combined mass be after the collision? show your work.

Solution Formula total velocity, V =mass 1 Ă— velocity 1 + mass 2 Ă— velocity 2 â• mass 1 + mass 2 Given mass 1 = 3.0 kg, velocity 1 = 1.4 m/s, mass 2 = 2.0 kg, velocity 2 = 0 m/s V = 3.0 Ă— 1.4 + 2.0 Ă— 0 â• 3.0 + 2.0 V = 0.84 m/s

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skyluke89 skyluke89 · Answer 2 · 2018-11-02T14:44:37+01:00

Answer:

0.84 m/s

Explanation:

we can solve the problem by using the law of conservation of momentum: the initial momentum must be equal to the final momentum, so we can write

[tex]p_i = p_f[/tex]

[tex]m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v[/tex]

where

[tex]m_1 = 3.0 kg[/tex] is the first mass

[tex]u_1=1.4 m/s[/tex] is the initial velocity of the first mass

[tex]m_2 = 2.0 kg[/tex] is the second mass

[tex]u_2 = 0[/tex] is the initial velocity of the second mass

[tex]v[/tex] is the final velocity of the two combined masses after the collision

Re-arranging the equation and substituting the numbers, we find

[tex]v=\frac{m_1 u_1 +m_2 u_2}{m_1+m_2}=\frac{(3.0)(1.4)-0}{3+2}=0.84 m/s[/tex]