Which reaction below represents the electron affinity of li? which reaction below represents the electron affinity of li? li(g) + e- → li-(g) li(g) + e- → li+(g) li+(g) → li(g) + e- li(g) → li+(g) + e- li+(g) + e- → li(g)?

Electron affinity is related to the formation of negative ions. Electron affinity can be defined as "the change in energy of a neutral atom when an electron is added to the atom forming a negative ion" To be more specific, energy (in kJ/mol) with regards to atoms (in a gaseous state/phase) Thus, the correct representation for the electron affinity of Li is [Li (g) + e- → Li- (g)]

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tutorareej tutorareej · Answer 2 · 2021-10-12T12:52:25+02:00

Answer:

The electron affinity of Li can be represented as [tex]\rm Li(g)\;+\;e^-\;\rightarrow\;Li^-(g)[/tex].

Explanation:

The electron affinity is the ability to gain electrons by the atom. On the addition of electrons, the atom imparts a negative charge on itself.

(a) [tex]\rm Li(g)\;+\;e^-\;\rightarrow\;Li^-(g)[/tex]

In this on the addition of electron, a negative charge is imparted.

(b) [tex]\rm Li\;+\;e^-\;\rightarrow\;Li^+(g)[/tex]

The metal is present in the solid-state and for the reaction to proceed it must be in the gaseous state. SO, this can't be the answer.

(c) [tex]\rm Li^+(g)\;\rightarrow\;Li(g)\;+\;e^-[/tex]

Since there is no addition of the electron in the atom, the reaction can not be the electron affinity reaction.

(d) [tex]\rm Li(g)\;\rightarrow\;Li^+(g)\;+\;e^-[/tex]

Li is in solid-state with no extra electron. It is unable to remove the electron.

(e) [tex]\rm Li^+(g)\;+\;e^-\;\rightarrow\;Li(g)[/tex]

This has the lithium in the ionic state and with a lack of one electron. On gaining an electron, the Li will result in the charged state of +2. So, this is not the correct representation.

The correct representation for the reaction is an option (a).

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