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Answer:
196 micrograms of potassium iodide per day
Explanation:
The question tell us that the requirement is 150 micrograms of iodine a day. Eating 150 micrograms of potassium iodide would not help because iodine would only be 76.45% of that sample. So we need to find a mass m, for which 76.45% is 150 micrograms:
[tex]\frac{76.45m}{100} =150*10^{-6}[/tex]
m = 196 micrograms of potassium iodide
The recommended daily allowance RDA) for iodine as 150 micrograms per day. The amount of potassium iodide (76.45%) should you consume to meet the RDA - 0.196 milligrams.
Given:
100 grams of KI contain = 76.45 grams of I
So, 1 gram of I will be present in = 100/76.45 grams of KI
Solution:
150 µg grams of Iodine will be contained in
=> ([tex]\frac{100}{76.45}[/tex]) × 150 × [tex]10^{-6}[/tex]
=> = 0.196 milligrams of KI
Thus, the amount of potassium iodide (76.45%) should you consume to meet the RDA - 0.196 milligrams.
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