Respuesta :
Sb2O3 + SbCl3 = Sb4O5Cl2
To balance Cl each side from Cl3 and Cl2 .. need 6 Cl
Sb2O3 + 2SbCl3 = 3Sb4O5Cl2
now to balance O.... O3 and O5 ... so need 15O
5Sb2O3 + 2SbCl3 = 3Sb4O5Cl2
Now check Sb each side 10 + 2 = 3x4 = 12 so OK
Answer:
The stoichiometric coefficient of the antimony(III) oxide is 5.
Explanation:
The compound [tex]Sb_4O_5Cl_2[/tex] is prepared by heating the antimony(III) oxide with antimony(III) chloride.
The balanced chemical reaction is given by:
[tex]5Sb_2O_3+2SbCl_3\rightarrow 3Sb_4O_5Cl_2[/tex]
The stoichiometric coefficient of the antimony(III) oxide is 5.