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The general form of the equation of a circle is Ax2 + By2 + Cx + Dy + E = 0, where A = B 0. If the circle has a radius of 3 units and the center at (0, 4), which set of values of A, B, C, D, and E correspond to the circle?

A.A = 0, B = 0, C = 2, D = 2, and E = 3
B.A = 1, B = 1, C = 8, D = 0, and E = 9
C.A = 1, B = 1, C = 0, D = -8, and E = 7
D.A = 1, B = 1, C = -8, D = 0, and E = 0
E.A = 1, B = 1, C = 8, D = 8, and E = 3

Respuesta :

the correct answer is b.
choixongdong
Ax^2 + By^2 + Cx +Dy + E = 0
radius = 3
standard form of the circle is
(x-a)² + (y-b)² = r², where (a,b) is the center, and r the radius
(x-0)^2 + (y-4)^2 = 9
x^2 + y^2 - 8y + 16 -9 = 0
x^2 + y^2 - 8y + 7 = 0
A=1, B=1,C= 0, D= -8, and E = 7

answer is
C.A = 1, B = 1, C = 0, D = -8, and E = 7

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