Respuesta :
Answer:
D. [tex]11j^2k^4[/tex]
Step-by-step explanation:
We are asked to find the GCF of [tex]44j^5k^4\text{ and }121j^2k^6[/tex].
Since we know that GCF of two numbers is the greatest number that is a factor of both of them.
First of all we will GCF of 44 and 121.
Factors of 44 are: 1, 2, 4, 11, 22, 44.
Factors of 121 are: 1, 11, 11, 121.
We can see that greatest common factor of 44 and 121 is 11.
Now let us find GCF of [tex]j^5\text{ and }j^2[/tex].
Factors of [tex]j^5[/tex] are: [tex]j*j*j*j*j[/tex]
Factors of [tex]j^2[/tex] are: [tex]j*j[/tex]
We can see that greatest common factor of [tex]j^5\text{ and }j^2[/tex] is [tex]j*j=j^2[/tex].
Now let us find GCF of [tex]k^4\text{ and }k^6[/tex].
Factors of [tex]k^4[/tex] are: [tex]k*k*k*k[/tex]
Factors of [tex]k^6[/tex] are:[tex]k*k*k*k*k*k[/tex]
We can see that greatest common factor of [tex]k^4\text{ and }k^6[/tex] is [tex]k*k*k*k=k^4[/tex].
Upon combining our all GCFs we will get,
[tex]11j^2k^4[/tex]
Therefore, GCF of [tex]44j^5k^4\text{ and }121j^2k^6[/tex] is [tex]11j^2k^4[/tex] and option D is the correct choice.
