Respuesta :
First you would solve for x. Since the equation follows the square of a binomial rule, you would solve it so.
(a - b)^2 = a^2 - 2ab + b^2
a^2 = x^2
a = x
b^2 = 36
b = 6
x^2 -12x + 36 = (x - 6)^2 = 0
x = 6
There is one real solution.
(a - b)^2 = a^2 - 2ab + b^2
a^2 = x^2
a = x
b^2 = 36
b = 6
x^2 -12x + 36 = (x - 6)^2 = 0
x = 6
There is one real solution.