FWUFFYFOX
contestada

An airplane initially travels at 10.0 m/s when passing the acceleration line. The airplane then accelerates at 8.00 m/s^2 until reaching its take off velocity of 40.0 m/s. What is the displacement of the plane during acceleration? A) 93.8 B) 3.75 C) 100 D)1590 please explain if able.

Respuesta :

W0lf93
The displacement of the plane during acceleration is 93.8 meters. The equation relating displacement, acceleration, and velocity is: Vf^2 = Vi^2 +2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is displacement. Plugging the given values into this equation: 40^2 = (10)^2 + 2*8*d => 1600 = 100+16d => solve for d: d = (1600-100)/16 = 93.8 meters.

Otras preguntas