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To loosen the lid on a jar of jam 8.9 cm in diameter a torque of 7.5 n·m must be applied to the circumference of the lid. if a jar wrench whose handle extends 13 cm from the center of the jar is attached to the lid, what is the minimum force required to open the jar?

Respuesta :

Refer to the diagram shown below.

F =  the minimum force required for opening the lid
r = 8.9/2 = 4.45 cm = 0.0445 m
P =  the applied force, aplied at a distance of 13 cm = 0.13 m.

Because the required torque is 7.5 N-m, therefore
(0.13 m)*(P N) = 7.5 N-m
P = 57.6923 N

The equation for the lever requires that
0.13P = 0.0445F = 7.5
Therefore
F = 7.5/.0445 = 168.54 N

Answer: 168.5 N

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