What square footage of artificial grass is needed to cover this portion of the course?

That figure is made up of 3 shapes.
A square, a rectangle, a semicircle.
The square has a side of 6 ft.
The semicircle has a radius of 4 ft.
The rectangle's width is the diameter of the semicircle, so it is 8 ft. The length of the rectangle is 18 ft.

Square:
A = s^2 = (6 ft)^2 = 36 ft^2

Rectangle:
A = LW = 18 ft * 8 ft = 144 ft^2

Semicircle:
A = (1/2) * pi * r^2 = (1/2) * pi * (4 ft)^2 = (1/2) * pi * 16 ft^2 = 8pi ft^2

Total area:
A = 36 ft^2 + 144 ft^2 + 8pi ft^2

A = (180 + 8pi) ft^2

bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-07-25T09:57:46+02:00

The square footage of artificial grass needed to cover the portion of the course is 8π+180 ft². Therefore, option A is the correct answer.

Given that, the figure has a rectangle, square and semicircle.

Dimension of a rectangle, length=18 ft and breadth=8 ft, dimension of a square, side=6 ft and semicircle, radius=4 ft.

What is the formula to find the area of a semicircle?

The formula to find the area of a semicircle is πr²/2.

Now, the area of a rectangle=Length×Breadth=18×8=144 ft².

The area of a square=Side²=6×6=36 ft².

The area of a semicircle =π×4²/2=8π

Thus, the total area =144+36+8π=8π+180 ft².

Therefore, the square footage of artificial grass needed to cover the portion of the course is 8π+180 ft². Therefore, option A is the correct answer.

To learn more about the area of a rectangle visit:

https://brainly.com/question/20693059.

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