Respuesta :
The frequency of the photon that has an energy of 8.0 × 10⁻¹⁵ J is 1.21 × 10¹⁹ /s.
The working out for the question is attached below.
Note that v= frequency; h= Plank's constant; E= Energy
The working out for the question is attached below.
Note that v= frequency; h= Plank's constant; E= Energy

Taking into account the definition of photon and energy of a photon, the frequency of the photon is 1.207 ×10¹⁹ Hz.
Definition of photon
You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".
Quantum of energy
The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.
The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:
E=h×f
Frequency of the photon
In this case, you know:
- h= 6.63*10⁻³⁴ Js
- E= 8.0×10⁻¹⁵ J
Replacing:
8.0×10⁻¹⁵ J= f × 6.63×10⁻³⁴ Js
Solving:
f= (8.0×10⁻¹⁵ J) ÷ (6.63×10⁻³⁴ Js)
f= 1.207 ×10¹⁹ Hz
Finally, the frequency of the photon is 1.207 ×10¹⁹ Hz.
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