For the answer to the question above asking what is A line passes through a point (-2, 5) and has a slope of. Points A(x, 3) and B(-2, y) lie on the line. The value of x is, and the value of y is?
y = mx + b
slope (m) = 2/3
(-2,5)...x = -2 and y = 5
now we sub and find b, the y int
5 = 2/3(-2) + b
5 = -4/3 + b
5 + 4/3 = b
15/3 + 4/3 = b
19/3 = b
so ur equation of the line is : y = 2/3x + 19/3
-2/3x + y = 19/3
-2x + 3y = 19
2x - 3y = -19
(x,3).....so sub in 3 for y
2x - 3(3) = -19
2x - 9 = -19
2x = -19 + 9
2x = - 10
x = -5......so point A is (-5,3)
(-2,y).....x = -2
2(-2) - 3y = -19
-4 - 3y = -19
-3y = -19 + 4
-3y = -15
y = 5......so the otherpoint is (-2,5)
