lola247
contestada

Solve the quadratic equation by completing the square.
0 = x2 – 6x + 4
–4 = x2 – 6x
–4 + 9 = (x2 – 6x + 9)
5 = (x – 3)2
What are the two solutions of the equation?

Respuesta :

Edufirst
1) equation given: 0 = x^2 - 6x + 4

2) transpose 4: - 4 = x^2 - 6x

3) complete squares: - 4 = (x^2 - 6x + 9) - 9

4) transpose  -9 and factor the square trinomial x^2 - 6x + 9:

- 4 + 9 = (x - 3)^2

5) combine like terms: 5 = (x - 3)^2

6) take square root on both sides: x - 3 = +/- √5

7) transpose - 3: x = 3 +/- √5

Answer: the two solutions are x = 3 - √5 and x = 3 + √5

The given quadratic equation is x^2 - 6x + 4 so, the two solutions are x = 3 - √5 and x = 3 + √5.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The given quadratic equation is x^2 - 6x + 4.

x^2 - 6x = -4

by Completing the square

- 4 = (x^2 - 6x + 9) - 9

Transpose -9 and factor the square trinomial

x^2 - 6x + 9

- 4 + 9 = (x - 3)^2

5 = (x - 3)^2

Take square root on both sides:

x - 3 = +/- √5

x = 3 +/- √5

Thus, the two solutions are x = 3 - √5 and x = 3 + √5.

Learn more about quadratic equations;

brainly.com/question/13197897

#SPJ3

Otras preguntas