Answer:
Speed of Driver A = [tex]\frac{\text{Number of miles Driven}}{Time} = \frac{31.25}{0.5}=\frac{125}{2}=\frac{218.75}{3.5}=\frac{312.5}{5}=62.50 miles/hour[/tex]
Speed of Driver B = [tex]\frac{y}{x}[/tex] , where y is number of miles driven and x is time taken.
As given Driver A travels at a slower rate than Driver B.
Speed of Driver A = 62.5 miles/hour
So, Speed of Driver B should be greater than 62.5 miles / hour.
In option A and C Speed of Driver B is 64 miles/hour and 66 miles/hour . In Both the cases Speed of Driver B is greater than Driver A.So option A and C are true which are : y = 64 x and y = 66 x