Given expression
[tex](4^2b^3c^{-5})(4^{-1}b^{-4}c^8)[/tex]
Rewriting each term
[tex]4^2 = 16[/tex]
[tex]b^3 = b^3[/tex]
[tex]c^{-5}= \frac{1}{c^5} [/tex]
[tex]4^{-1} = \frac{1}{4} [/tex]
[tex]b^{-4} = \frac{1}{b^4} [/tex]
[tex]c^8 = c^8[/tex]
Put them back together
[tex](16)(b^3)( \frac{1}{c^5} )( \frac{1}{4})( \frac{1}{b^4})(c^8) [/tex]
[tex]( \frac{16}{4})( \frac{b^3}{b^4})( \frac{c^8}{c^5} )[/tex]
[tex]4(b^{3-4})(c^{8-5})[/tex]
[tex]4b^{-1}c^3[/tex]
[tex] \frac{4c^3}{b} [/tex]
