Respuesta :
because the zeros are 1, -1, 2, 4, the factors are
(x-1)(x+1)(x-2)(x-4)
to put in standard form, you have to write the terms in order by degree, so you have to expand the above expression:
(x^2-1)(x^2-6x+8)
further expand it:
x^4-6x^3+7x^2+6x-8
(x-1)(x+1)(x-2)(x-4)
to put in standard form, you have to write the terms in order by degree, so you have to expand the above expression:
(x^2-1)(x^2-6x+8)
further expand it:
x^4-6x^3+7x^2+6x-8
The polynomial function obtained from the Zeros given, written in standard form is x⁴ - 6x³ + 7x² + 6x - 8
Polynomial with Zeros 1, - 1, 2 and 4 can be expressed thus :
x = 1 :
- x - 1
x = - 1 :
- x + 1
x = 2 :
- x - 2
x = 4 :
- x - 4
Hence, we have :
(x - 1)(x + 1)(x - 2)(x - 4) = 0
We can then expand ;
(x - 1)(x + 1) = x² + x - x - 1 = x² - 1
(x² - 1)(x - 2) = x³ - 2x²-x + 2
(x³ - 2x² - x + 2)(x - 4)
x⁴ - 4x³ - 2x³ + 8x² - x² + 4x + 2x - 8
x⁴ - 6x³ + 7x² + 6x - 8
Hence, the polynomial function written in standard form is x⁴ - 6x³ + 7x² + 6x - 8
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