contestada

the graph of which of the following inequalities has open circles on -8 and 2 with a line segment between them

A. |x + 3| < -5
B. |x + 8| < 2
C. |x + 3| < 5

Respuesta :

Catya
A. Can NOT be true since the absolute value will be greater than 0.
B. Does NOT work with the solutions -8 and 2.
C.√ Correct
|-8+3| = 5
|2+3| = 5

Answer:

Option C is correct answer.

Step-by-step explanation:

since -8 and 2 are end points with open circle therefore

If  l x -a l < R

means  -R< x-a< R

              -R+a<x <a+R

 Comparing it with -8<x<2 gives

                  a-R= -8

                  a+R= 2

  Adding both ,we get  2a = -6  which equals a =-3

        plugging the value a =-3 in equation a+R=2

          -3+R=2 gives R =5

therefore   the inequality is lx-(-3) l < 5

on simplifying we get

                   l x+3< 5

Option C is the correct answer