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It is necessary to determine the specific heat of an unknown object. The mass of the object is 201.0 g. It is determined experimentally that it takes 15.0 J to raise the temperature 10.0 ° C. What is the specific heat of the object?

Respuesta :

AyoV
mass = 0.201kg
Energy = 15J
temperature change = 10C

Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)

we can rearrange this to make specific heat capacity the subject

c =[tex] \frac{E}{m\theta} [/tex]

c =[tex] \frac{15}{2.01} [/tex]
c =7.46268657

Answer:

The specific heat of the object is 0.0074 J/(g °C)

Explanation:

Data

mass, m = 201 g

Heat, Q = 15 J

temperature change, ΔT = 10 °C

specific heat, cp = ?

The equation that relates these variables is:

Q = m*cp*ΔT

Solving for specific heat we get:

cp = Q/(m*ΔT)

Replacing with data (units are ommited):

cp = 15/(201*10)

cp = 0.0074 J/(g °C)

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