The two figures are similar. Find the ratios (red to blue) of the perimeters and of the areas. Write the ratios as fractions in simplest form.

Answer:
Ratio of perimeters = [tex]\frac{3}{4}[/tex]
Ratio of areas = [tex]\frac{9}{16}[/tex]
Step-by-step explanation:
Thinking process:
The ratio of the parameters is given by the following:
[tex]ratio = \frac{length of side 1}{length of side 2}[/tex]
=[tex]\frac{6}{8} \\= \frac{3}{4}[/tex]
The ratio of the areas is given by:
[tex]ratio = (\frac{length of side 1}{length of side 2}) ^{2}[/tex]
= [tex](\frac{6}{8}) ^{2}[/tex]
= [tex]\frac{36}{64}[/tex]
= [tex]\frac{9}{16}[/tex]
The values of the fraction of the perimeter and the area of the triangles will be 3/4 and 9/16 respectively.
The fraction of the perimeters will be:
= 18cm/24cm = 3/4
The fraction of the areas will be:
= 18cm²/32cm²
= 9/16
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