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Will give brainliest!
How long will it take the tool to fall to the ground?
The function for objects dropped from a height where t is the time in seconds, h is the height in feet at time t, and h0 is the initial height is h(t)=-16t^2+h0. The building I already figured to be 162 feet.
Thank You!!

Respuesta :

check the picture below, it hits the ground when y = 0.

[tex]\bf ~~~~~~\textit{initial velocity}\\\\ \begin{array}{llll} ~~~~~~\textit{in feet}\\\\ h(t) = -16t^2+v_ot+h_o \\\\ \end{array} \quad \begin{cases} v_o=\stackrel{0}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{162}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-16t^2+0t+162\implies 0=-16t^2+162\implies 16t^2=162 \\\\\\ t=\cfrac{162}{16}\implies t=\cfrac{81}{8}\implies t=10\frac{1}{8}[/tex]
Ver imagen jdoe0001